1樓：劍小風
看了上面幾位的** ：應該都寫錯了
樓主的問題是：s等於 1到n之間每個整數的階乘相加，而不是n的階乘我沒理解錯吧？
稍等 完畢：
在模組中輸入**：
public function fac(n as integer) as long '在模組中用public(公用的)定義函式過程
dim i as integer, j as integer, s as long
for i = 1 to n
s = 1
for j = 1 to i
s = s * j
next j
fac = fac + s
next i
end function
在窗體中輸入**：
private sub form_click()dim s as long
dim n as integer
n = inputbox("請輸入一個整數")s = fac(n)
print s
end sub
2樓：
雙擊模組，選插入選單裡面的插入過程，選插入函式，命名為fac**如下：
public function fac(n as integer)dim i as integer, s as integerfor i = 1 to n
s = s + i
next
fac = s
end function
3樓：匿名使用者
private sub command1_click() 過程方法dim i as integer
for i = 1 to 10
sum = sum + jc(i)
next
msgbox sum
end sub
function jc(a as integer) 函式方法jc = 1
for i = 1 to a
jc = jc * i
next
end function請參考
4樓：匿名使用者
private function fac(byval n as integer) as single
dim i as integer
dim j as single
j = 1
for i = 1 to n
j = j * i
next i
fac = j
end function
vb程式設計"編寫一個求n!的階乘函式f(n),利用該函式計算二項式係數cmn=m!/(n!*(m-n)!
5樓：vb愛好者
列如bai
：dim a, b as integer
dim s as long
b = val(text1)
s = 1
for a = 1 to n
s = s * n
label1.caption = "你輸出du的" + str(n) + "的結果為" + str(s)
這只是zhi一個dao列子，你可內以開動容腦筋
6樓：匿名使用者
private sub command1_click()dim m as integer, n as integerm = int(inputbox("輸入第一個整數專"))n = int(inputbox("輸入第一個整數"))
if m >= n then
cmn = jiecheng(m) / (jiecheng(n) * jiecheng(m - n))
print cmn
else: msgbox "輸入資料有錯
屬"end if
end sub
private function jiecheng(x as integer) as double
jiecheng = 1
for i = 1 to x
jiecheng = jiecheng * inext
end function
用vb編寫程式，求s=a!+b!+c!，階乘的計算分別用sub過程和function過程兩種方法來實現
7樓：匿名使用者
（1）用sub實現的過程bai
如下：du
dim a,b,c,s
a=1b=2
c=3s=0
sub jc(x)
dim v
v=1while x>0
v=v*x
x=x-1
wend
s=s+v
end sub
jc a
jc b
jc c
msgbox s
（2）用function的過程zhi如下
function
function jc(a)
if a>0 then
jc=a*jc(a-1)
else
jc=1
end if
end function
dim s,a,b,c
a=4b=7
c=5s=jc(a)+jc(b)+jc(c)
8樓：網海1書生
：private sub command1_click()
dim a as long, b as long, c as long
a = val(inputbox("請輸入一個大於0的整數a："))
b = val(inputbox("請輸入一個大於0的整數b："))
c = val(inputbox("請輸入一個大於0的整數c："))
if a > 0 and b > 0 and c > 0 then
n1 a
n1 b
n1 c
msgbox "a!+b!+c!=" & a + b + c
end if
end sub
sub n1(n as long)
dim i as long, s as long
s = 1
for i = 2 to n
s = s * i
next
n = s
end sub
function實現：
private sub command1_click()
dim a as long, b as long, c as long
a = val(inputbox("請輸入一個大於0的整數a："))
b = val(inputbox("請輸入一個大於0的整數b："))
c = val(inputbox("請輸入一個大於0的整數c："))
if a > 0 and b > 0 and c > 0 then
msgbox "a!+b!+c!=" & n2(a) + n2(b) + n2(c)
end if
end sub
function n2(n as long) as long
dim i as long
n2 = 1
for i = 2 to n
n2 = n2 * i
next
end function
請注意：輸入的數字不能太大，因為受long型最大值的限制，計算13!即溢位。要想計算更大的數值，可使用double數值型別
求vb題**：求任意個數的階乘累計和。s=1!+2！+3！+...+n!，n由使用者輸入。
9樓：烽火魂
private sub command1_click()
dim i as double
dim n as double
dim sum as double
sum = 0
if not isnumeric(text1.text) then '判斷是否為數字，不是數字就彈出對話方塊並對出過程
call msg '呼叫已經寫好的過程
exit sub
end if
n = text1.text
if n < 1 then '判斷是否小於1 ，如果小於1就呼叫已經定義好的過程彈出對話方塊
call msg
exit sub
end if
for n = 1 to n '求1!到n!階乘迴圈n次
sum = sum + func(n) '呼叫求第n數的的階乘的函式，計算前1!+n!的和
next n
msgbox "1!+2!+3!+......+n!為" & sum, vbinformation, "結果"
end sub
'求第n個數的階乘函式
function func(n as double) as double
dim i as double
dim jc as double
jc = 1
for i = 1 to n
jc = jc * i
next i
func = jc
end function
'彈出對話方塊
sub msg()
msgbox "你輸入資料不正確", vbinformation, "提示"
end sub
10樓：
一樓的很複雜，給你來個簡單的：
private sub commandbutton1_click()dim i, s, k
dim n
aaa: n = inputbox("請輸入大於等於1的數字")if val(n) >= 1 then
if len(n) = 0 then endfor i = 1 to n
s = s + i * i
next
msgbox "從1到" & n & "階乘累計和為：" & selse
k = msgbox("你輸入資料不符合標準，請重輸入：", vbokcancel, vbinformation, "提示")
if k = vbok then
goto aaa
else
endend if
end if
end sub
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